Vprašanje # f472a

Vprašanje # f472a
Anonim

Odgovor:

# z = y / (3y / x + 3/2) #

Pojasnilo:

Najprej želite obrniti # x #, # y # in # z # na dejavnike. V ta namen uporabite logaritem naperian:

#color (siva) (Opomba: ln (a * b) = ln (a) + ln (b) in ln (a ^ b) = bln (a)) #

#ln (2 ^ x) = ln (3 ^ y) = ln ((24sqrt3) ^ z) #

# = xln (2) = yln (3) = zln (24sqrt3) #

Nato izolirajte # z #:

#z = (yln (3)) / (ln (24sqrt3)) = (yln (3)) / (ln (3 * 2 ^ 3) + ln (3 ^ (1/2))) #

# = (yln (3)) / (3ln (2) + ln (3) + ln (3) / 2) #

Zamenjati #ln (2) # z # y / xln (3) #

# z = (yln (3)) / (3y / xln (3) + ln (3) + ln (3) / 2) #

# = (ycancel (ln (3))) / ((3y / x + 1 + 1/2) prekliči (ln (3))) = y / (3y / x + 3/2) #