Kako najdete vse ničle 4x ^ 3-4x ^ 2-9x + 9 z 1 kot nič?

Kako najdete vse ničle 4x ^ 3-4x ^ 2-9x + 9 z 1 kot nič?
Anonim

Odgovor:

Tri korenine so # x = -3 / 2, 1, 3/2 #

Opomba Ne najdem simbola dolge delitve, tako da bom uporabil simbol kvadratnega korena na njegovem mestu.

Pojasnilo:

#f (x) = 4x ^ 3-4x ^ 2-9x + 9 #

#f (1) = 4 * 1 ^ 3-4 * 1 ^ 2-9 * 1 + 9 = 4-4-9 + 9 = 0 #

To pomeni, da je x = 1 koren in # (x-1) # je faktor tega polinoma.

Moramo najti druge dejavnike, to naredimo tako, da f (x) delimo z # (x-1) # za iskanje drugih dejavnikov.

# {4x ^ 3-4x ^ 2-9x + 9} / {x-1} #

# (x-1) sqrt (4x ^ 3-4x ^ 2-9x + 9) #

Od # (x * 4x ^ 2) = 4 x ^ 3 # dobimo # 4x ^ 2 # kot izraz v faktorju

# # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # 4x ^ 2 #

# (x-1) sqrt (4x ^ 3-4x ^ 2-9x + 9) #

poiskati moramo preostanek, da bi našli, kaj je še treba najti.

smo # 4x ^ 2 * (x-1) = 4x ^ 3-4x ^ 2 #

# # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # 4x ^ 2 #

# (x-1) sqrt (4x ^ 3-4x ^ 2-9x + 9) #

# # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # 4x ^ 3-4x ^ 2 #

Odštejemo to, da dobimo 0

# # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # 4x ^ 2 #

# (x-1) sqrt (4x ^ 3-4x ^ 2-9x + 9) #

# # # # # # # # # # # # # # # # # # # # # # # # #ul {- (4x ^ 3-4x ^ 2)} #

# # # # # # # # # # # # # # # # # # # # # # # # # # # # # ## # # # # 0x ^ 3-0x ^ 2 #

ta nič pomeni, da ne obstaja noben linearni izraz in da znižujemo naslednje pogoje.

# # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # 4x ^ 2 + 0 x #

# (x-1) sqrt (4x ^ 3-4x ^ 2-9x + 9) #

# # # # # # # # # # # # # # # # # # # # # # # # #ul {- (4x ^ 3-4x ^ 2)} #

# # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # 0x ^ 3-0x ^ 2 # # -9x + 9 #

# x * -9 = -9x # tako je naslednji izraz #-9#

# # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # 4x ^ 2 + 0 x -9 #

# (x-1) sqrt (4x ^ 3-4x ^ 2-9x + 9) #

# # # # # # # # # # # # # # # # # # # # # # # # #ul {- (4x ^ 3-4x ^ 2)} #

# # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # 0x ^ 3-0x ^ 2 # # -9x + 9 #

# -9 * (x-1) = - 9x + 9 #

# # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # 4x ^ 2 + 0 x -9 #

# (x-1) sqrt (4x ^ 3-4x ^ 2-9x + 9) #

# # # # # # # # # # # # # # # # # # # # # # # # #ul {- (4x ^ 3-4x ^ 2)} #

# # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # 0x ^ 3-0x ^ 2 # # -9x + 9 #

# # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # #ul {- (- 9x + 9)} #

# # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # 4x ^ 2 + 0 x -9 #

# (x-1) sqrt (4x ^ 3-4x ^ 2-9x + 9) #

# # # # # # # # # # # # # # # # # # # # # # # # #ul {- (4x ^ 3-4x ^ 2)} #

# # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # 0x ^ 3-0x ^ 2 # # -9x + 9 #

# # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # #ul {- (- 9x + 9)} #

# # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # #0#

Torej # (x-1) (4x ^ 2 -9) # brez opomnika (to lahko preverite z razširitvijo). To moramo popolnoma upoštevati.

# (4x ^ 2 -9) # je razlika kvadratov s faktorji # (2x-3) * (2x + 3) #

Imamo # (x-1) * (2x-3) * (2x + 3) = 0 #

# 2x-3 = 0 # nam daje koren # x = 3/2 # in # 2x + 3 = 0 # nam daje koren # x = -3 / 2 #

Korenine so # x = -3 / 2, 1, 3/2 #