Odgovor:
# abc = 1872
Pojasnilo:
Glede na to
# sqrt {104 sqrt6 + 468 sqrt10 + 144} sqrt15 + 2006} = a sqrt2 + b t
# 104 sqrt6 + 468 sqrt10 + 144 sqrt15 + 2006 = (a sqrt2 + b; sqrt3 + c; sqrt5) ^ 2 #
# 104 sqrt6 + 468 sqrt10 + 144 sqrt15 + 2006 = 2a ^ 2 + 3b ^ 2 + 5c ^ 2 + ab kvadrat + ac t
S primerjavo koeficientov # sqrt2, t & # t na obeh straneh, ki jih dobimo
# ab = 104 #
# ac = 468 #
# bc = 144 #
Če pomnožimo tri enačbe, dobimo
#ab cdot ac cdot bc = cdot 468 cdot 144 #
# (abc) ^ 2 = 104 cdot 468 cdot 144 #
# abc = sqrt {104; cdot 468; cdot 144} # #
# abc = 12 cdot156 t
# abc = 1872