Kako najdete korenine x ^ 3-6x ^ 2 + 13x-10 = 0?

Kako najdete korenine x ^ 3-6x ^ 2 + 13x-10 = 0?
Anonim

Odgovor:

# x = 2 #

Pojasnilo:

# x ^ 3-6x ^ 2 + 13x-10 = 0 #

# x ^ 3-3 (x) ^ 2 (2) +3 (2) ^ 2x + x-2 ^ 3-2 = 0 #

# (x ^ 3-3 (x) ^ 2 (2) + 3x (2) ^ 2-2 ^ 3) + x-2 = 0 #

S pomočjo polinomske identitete, ki sledi, lahko faktoriziramo

# (a-b) ^ 3 = a ^ 3-3a ^ 2b + 3ab ^ 2 + b ^ 3 #

v našem primeru # a = x # in # b = 2 #

Torej, # (x-2) ^ 3 + (x-2) = 0 # pri sprejemanju # x-2 # kot skupni dejavnik

# (x-2) ((x-2) ^ 2 + 1) = 0 #

# (x-2) (x ^ 2-4x + 4 + 1) = 0 #

# (x-2) (x ^ 2-4x + 5) = 0 #

# x-2 = 0 # potem # x = 2 #

Or

# x ^ 2-4x + 5 = 0 #

#delta = (- 4) ^ 2-4 (1) (5) = 16-20 = -4 <0 #

#delta <0rArr # ni korena v R