Kako narediti to vprašanje?

Odgovor:

# a = 2 # in # b = 5 #

Pojasnilo:

Tukaj #a (x-3) ^ 3 + b #

# = a (x ^ 3-3 * x ^ 2 * 3 + 3 * x * 3 ^ 2-3 ^ 3) + b #

# = ax ^ 3-9ax ^ 2 + 27ax-27a + b #

Primerjava

# ax ^ 3-9ax ^ 2 + 27ax-27a + b # in # 2x ^ 3-18x ^ 2 + 54x-49 #,dobimo

# rarrax ^ 3 = 2x ^ 3 #

# rarra = 2 #

in # b-27a = -49

# rarrb-27 * 2 = -49

# rarrb-54 = -49

# rarrb = 5 #

Torej, # a = 2 # in # b = 5 #.