Odgovor:
Nule na # x = -2 # in # x = -3 #
Pojasnilo:
# x ^ 2 + 5x = -6 #
#hArrcolor (bela) ("XXX") x ^ x + 5x + 6 = 0 #
#hArrcolor (bela) ("XXX") (x + 2) (x + 3) = 0 #
prav tako
#barva (bela) ("XXX") (x + 2) = 0barva (bela) ("XX") rarrcolor (bela) ("XX") x = -2 #
ali
#barva (bela) ("XXX") (x + 3) = 0barva (bela) ("XX") rarrcolor (bela) ("XX") x = -3