Če je f (x) = sqrt (1 + x) in g (x) = (3x ^ 2) / (x ^ 2 + 1), kaj je g [f (x)]?

Če je f (x) = sqrt (1 + x) in g (x) = (3x ^ 2) / (x ^ 2 + 1), kaj je g [f (x)]?
Anonim

Odgovor:

Odgovor je:

#g f (x) = 3 (1 + x) / (2 + x) #

Pojasnilo:

#f (x) = sqrt (1 + x) #

#g (x) = (3x ^ 2) / (x ^ 2 + 1) #

Za #g f (x) # nadomestek #f (x) # namesto # x # v #g (x) # funkcija:

#g f (x) = (3sqrt (1 + x) ^ 2) / (sqrt (1 + x) ^ 2 + 1) #

#g f (x) = (3 (1 + x)) / ((1 + x) +1) #

#g f (x) = 3 (1 + x) / (1 + x + 1) #

#g f (x) = 3 (1 + x) / (2 + x) #