Odgovor:
# m = log_2 (35) -1 ~~ 4.13 #
Pojasnilo:
Začnemo z odštevanjem #9# z obeh strani:
# 2 ^ (m + 1) + prekliči (9-9) = 44-9 #
# 2 ^ (m + 1) = 35 #
Vzemite # log_2 # na obeh straneh:
#cancel (log_2) (prekliči (2) ^ (m + 1)) = log_2 (35) #
# m + 1 = log_2 (35) #
Odštej #1# na obeh straneh:
# m + prekliči (1-1) = log_2 (35) -1
# m = log_2 (35) -1 ~~ 4.13 #
Odgovor:
# m ~~ 4.129 # (4sf)
Pojasnilo:
# 2 ^ (m + 1) + 9 = 44 #
# 2 ^ (m + 1) = 35 #
V obliki logaritma je to:
# log_2 (35) = m + 1 #
Tega se spominjam skoraj tako, kot se držim 2 kot bazo in preklopim druge številke.
# m = log_2 (35) -1 #
# m ~~ 4.129 # (4sf)
Odgovor:
# m = (log35-log2) / log2 #
Pojasnilo:
# 2 ^ (m + 1) + 9 = 44 #
# 2 ^ (m + 1) = 44-9 = 35 #
#log (2 ^ (m + 1)) = log35 "" # (z logaritmsko osnovo #10# na obeh straneh)
#log (2 ^ m * 2) = log35 #
# log2 ^ m + log2 = log35 #
# log2 ^ m = log35-log2 #
# mlog2 = log35-log2 #
# m = (log35-log2) / log2 #
