Odgovor:
Odgovor je # ((x), (y), (z)) = ((- 2z-3), (2z + 3), (z)) #
Pojasnilo:
Gaussovo izkoreninjenje izvajamo z razširjeno matrico
#((1,2,-2,:,3),(1,3,-4,:,6),(4,5,-2,:,3))#
# R3larrR3-4R1 #, #=>#, #((1,2,-2,:,3),(1,3,-4,:,6),(0,-3, 6,:,-9))#
# R2larrR2-R1 #, #=>#, #((1,2,-2,:,3),(0,1,-2,:,3),(0,-3, 6,:,-9))#
# R3larrR2 + 3R2 #, #=>#, #((1,2,-2,:,3),(0,1,-2,:,3),(0,0, 0,:,0))#
# R1larrR1-2R2 #, #=>#, #((1,0,2,:,-3),(0,1,-2,:,3),(0,0, 0,:,0))#
Zato so rešitve
# x = -2z-3 #
# y = 2z + 3 #
# z = #prost