Odgovor:
#barva (modra) (x = 4) barva (bela) ("XX") ali barva (bela) ("XX") barva (modra) (x = -2) #
Pojasnilo:
Glede na
#barva (bela) ("XXX") 2 / (x + 6) + (2x) / (x + 4) = (3x) / (x + 6) #
#rArr barva (bela) ("XX") (2x) / (x + 4) = (3x-2) / (x + 6) #
navzkrižno množenje:
#barva (bela) ("XXX") (2x) xx (x + 6) = (3x-2) xx (x + 4) #
#rArrcolor (bela) ("XX") 2x ^ 2 + 12x = 3x ^ 2 + 10x-8 #
#rArrcolor (bela) ("XX") x ^ 2-2x-8 = 0 #
#rArrcolor (bel) ("XX") (x-4) (x + 2) = 0 #
#rArr {:(x-4 = 0, barva (bela) ("XX") ali barva (bela) ("XX"), x + 2 = 0), (rarrx = 4,, rarrx = -2):} #