Odgovor:
# y = 1 / 2x + 2 #
Pojasnilo:
#f (x) = x + 2 / x #, # D_f = RR #*# = (- oo, 0) uu (0, + oo) #
Za #x! = 0 # imamo
#f '(x) = (x + 2 / x)' = 1-2 / x ^ 2 #
Enačba tangentne črte na #M (2, f (2)) # bo
# y-f (2) = f '(2) (x-2) # #<=>#
# y-3 = (1-2 / 4) (x-2) #<=>#
# y-3 = 1/2 (x-2) # #<=>#
# y = 1 / 2x + 2 #