Odgovor:
# S = {pi / 6 + 2pin, (5pi) / 6 + 2pina, x = pi / 2 + 2pin} #
Pojasnilo:
Uporabite lastnost dvojnega argumenta:
# cos2A = 1-2min ^ 2A #
# 1-2sin ^ 2x + 3sinx-2 = 0 #
# 2sin ^ 2x-3sinx + 1 = 0 #
# (2sinx-1) (sinx-1) = 0 #
# 2sinx-1 = 0 ali sinx-1 = 0 #
# sinx = 1/2 ali sinx = 1 #
# x = sin ^ -1 (1/2) ali x = sin ^ -1 1 #
# x = pi / 6 + 2pin, (5pi) / 6 + 2pina ali x = pi / 2 + 2pin #
# S = {pi / 6 + 2pin, (5pi) / 6 + 2pina, x = pi / 2 + 2pin} #
