Pretvorite polarno enačbo v pravokotno enačbo ?! percalc hw pomoč?

Odgovor:

Pojasnilo:

Najprej pomnožite vsako stran z # 1-sintheta # dobiti:

# r-rsintheta = 4/5 #

# r ^ 2 = x ^ 2 + y ^ 2 #

# rsintheta = y #

#sqrt (x ^ 2 + y ^ 2) = 4/5 + y #

# x ^ 2 + y ^ 2 = 16/25 + (8y) / 5 + y ^ 2 #

# x ^ 2 = 16/25 + (8y) / 5 #

# 25x ^ 2 = 16 + 40y #

# 25x ^ 2-40y-16 = 0 #

Ta odgovor se ne ujema z nobenim od odgovorov, zato D.

Kako pretvorite y = 3x ^ 2-5x-y ^ 2 v polarno enačbo?

R = - (sintheta + 5costheta) / (sin ^ 2theta-3cos ^ 2theta) Za to potrebujemo naslednje: x = rcostheta y = rsintheta rsintheta = 3 (rcostheta) ^ 2-5 (rcostheta) - (rsintheta) ^ 2 rsintheta = 3r ^ 2cos ^ 2theta-5rcostheta-r ^ 2sin ^ 2theta rsintheta + r ^ 2sin ^ 2theta = 3r ^ 2cos ^ 2theta-5rcostheta sintheta + rsin ^ 2theta = 3rcos ^ 2theta-5costheta rsin ^ 2theta-3rcos ^ 2theta = - sintheta-5costheta r = (- sintheta-5costheta) / (sin ^ 2theta-3cos ^ 2theta) = - (sintheta + 5costheta) / (sin ^ 2theta-3cos ^ 2theta)

Kako pretvorite y = 2y ^ 2 + 3x ^ 2-2xy v polarno enačbo?

R = sintheta / (2sin ^ 2theta + 3cos ^ 2theta-sin (2theta)) Za to bomo potrebovali: x = rcostheta y = rsintheta rsintheta = 2 (rsintheta) ^ 2 + 3 (rcostheta) ^ 2-2 (rcostheta) (rsintheta) rsintheta = 2r ^ 2sin ^ 2theta + 3r ^ 2cos ^ 2theta-2r ^ 2costhetasintheta sintheta = 2rsin ^ 2theta + 3rcos ^ 2theta-2rcosthetasintheta sintheta = 2rsin ^ 2theta + 3rcos ^ 2theta-rsin (2theta) sintheta = r ^ 2theta + 3cos ^ 2theta-sin (2theta)) r = sintheta / (2sin ^ 2theta + 3cos ^ 2theta-sin (2theta))

Kako spremenite pravokotno enačbo x + y = 0 v polarno obliko?

Tan theta = -1 x + y = 0 r * cos theta + r * sin theta = 0 cos theta + sin theta = 0 cos theta / cos theta + sin theta / cos theta = 0 / cos theta 1 + tan theta = 0 tan theta = -1 Bog blagoslovi .... Upam, da je razlaga koristna.